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anygoal [31]
3 years ago
9

A pattern exists in the sum of the interior angles of polygons. The sum of the interior angles of a

Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

1,620 degrees.

Step-by-step explanation:

It has a steady pattern. 180 x 2 = 360, which is quadrilateral. 180 x 3 = 540, which is a pentagon. so, 180 x 9 = 1,620

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What is the length of JM in the given figure?
umka21 [38]

Answer:  B. 30

<u>Step-by-step explanation:</u>

When given a secant and a tangent, the formula is:

exterior of secant × secant = tangent²

                     KM   ×    JK     =    LK²

                      10   ×  (JM + 10) = 20²

                            10JM + 100 = 400

                                     10JM = 300

                                         JM =  30

7 0
3 years ago
What is 33.5 % as a Decimal and a fraction?
Stolb23 [73]

p\%=\dfrac{p}{100}\\\\33.5\%=\dfrac{33.5}{100}=\dfrac{33.5\cdot10}{100\cdot10}=\dfrac{335}{1000}\\\\\dfrac{335}{1000}=0.335\\\\\dfrac{335}{1000}=\dfrac{335:5}{1000:5}=\dfrac{67}{200}

Answer:\\\\\boxed{33.5\%=0.335}\\\boxed{33.5\%=\dfrac{67}{200}}

5 0
3 years ago
Read 2 more answers
The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

5 0
3 years ago
If ON = MN, find MN.<br> A 4<br> B. 5<br> C. 4 square root 2<br> D. 4 square root 30
elena-14-01-66 [18.8K]

Answer:

c

Step-by-step explanation:

ON=MN, so triangle onm is a right isosclese triangle, so ON=NM=4 square root 2

4 0
3 years ago
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Answer:

B has a higer probability

Step-by-step explanation:

8 0
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