First add the 8 to both sides, canceling out the 8 in the right and adding it to the 19 on the left, making it 27. Multiplying undoes division so, After that, multiply by three on both sides, canceling out the three on the right and multiply 27 by 3, making it 81.
Answer:
you have to use the quadratic equation to find the zeros
Step-by-step explanation:
Answers:
P(A) = 7/12
P(B) = 1/2
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Explanation:
To see how I calculated P(A), check out this link to this very similar question
brainly.com/question/27669586
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Now to calculate P(B)
If a number is divisible by 2, then the number is a multiple of 2.
In other words, the number is even.
Counting through the values in the table, you should find that there are 18 sums that are even (2, 4, 6, 8, 10 and 12). Refer to the dice chart below.
Here's a further breakdown
- 1 copy of "2"
- 3 copies of "4"
- 5 copies of "6"
- 5 copies of "8"
- 3 copies of "10"
- 1 copy of 12
Side note: We have nice symmetry going on.
There are 1+3+5+5+3+1 = 18 values total that are even numbers. The other half are odd numbers of course.
P(B) = 18/36 = (1*18)/(2*18) = 1/2
4+6^2+9•3-10
PEMDAS
P=parentheses
E=exponent
m=multiplication
d=division
a=addition
s=subtraction
*no parentheses in this equation
*exponent = 6^2
6^2=36
4+36+9•3-10
*multiplication = 9•3
9•3=27
4+36+27-10
*addition=4+36+27
4+36+27=67
67-10
*subtraction=67-10
67=10=57
ANSWER=57
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