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TiliK225 [7]
2 years ago
10

PLS HELP!!!!!!!!

Mathematics
1 answer:
fiasKO [112]2 years ago
4 0

Answer:

cant i help you i know that but i forget

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Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0
1 year ago
Helpp me asapp with this problem plss will crown brainiest !!!!
Evgen [1.6K]

Answer:

see below

Step-by-step explanation:

Since RT bisects QRS

1/2  QRS = TRS

1/2 ( 9x+214) = -9x+53

Multiply each side by 2

9x +214 = -18x+ 106

Add 18x from each side

9x +214+18x = 106

27x +214 = 106

Subtract 214 from each side

27x = 106-214

27x =-108

Divide by 27

27x/27 = -108/27

x = -4

TRS = -9x+53

     =-9 *-4 +53

     = 36+ 53

    =89

4 0
3 years ago
Read 2 more answers
5. h(x)=0.5x - 1 with domain (-♾, 4) what is the range
Rudiy27

We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in (-\infty,4).

Let's try x=4 even though we are forbidden to put 4 inside h we are still able to do so.

So h(4)=0.5\cdot4-1=2-1=1 what we just got is the upper limit of the range. The lower limit is h(-\infty)=-\infty.

So the range is just (-\infty, 1).

Hope this helps :)

6 0
3 years ago
Which trigonometric value is equal to cos 62°?
Dennis_Churaev [7]
You answer is SIN 28°
5 0
3 years ago
Read 2 more answers
Solve. 2(2z – 4) = 4​
Oxana [17]

Answer:

z = 3

Step-by-step explanation:

1) Divide both sides by 2.

2z - 4 =  \frac{4}{2}

2) Simplify 4/2 to 2.

2z - 4 = 2

3) Add 4 to both sides.

2z = 2 + 4

4) Simplify 2 + 4 to 6.

2z = 6

5) Divide both sides by 2.

z =  \frac{6}{2}

6) Simplify 6/2 to 3.

z = 3

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4 0
2 years ago
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