can be simplified to by adding the 7 and 10 to get
.
cannot be simplified any more by combining like terms.
By distributing the 2b into the parentheses, you can simplify the expression:
Here you can just add:
Thus, the only expression that cannot simplify any more using adding like terms is the second,
.
Answer:
<span>=3<span>√6</span>−3<span>√5</span></span>
Explanation:
<span>3<span><span>√5</span>+<span>√6</span></span></span>
We rationalise the denominator by multiplying the expression by the conjugate of the denominator. <span><span>√5</span>−<span>√6</span></span>
<span><span>3⋅<span>(<span>√5</span>−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span>
<span>=<span><span>3⋅<span>(<span>√5</span>)</span>+3⋅<span>(−<span>√6</span>)</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span>(<span>√5</span>+<span>√6</span>)</span>⋅<span>(<span>√5</span>−<span>√6</span>)</span></span></span></span>
<span>Applying identity
<span><span>(a+b)</span><span>(a−b)</span>=<span>a2</span>−<span>b2</span></span> to the denominator.</span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span><span><span>(<span>√5</span>)</span>2</span>−<span><span>(<span>√6</span>)</span>2</span></span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>5−6</span></span></span>
<span>=<span><span>3<span>√5</span>−3<span>√6</span></span><span>−1</span></span></span>
<span>=−3<span>√5</span>+3<span>√6</span></span>
<span>=3<span>√6</span>−3<span>√<span>5
</span></span></span>
X=-4 cause
-2=x+2
Then -4=x
Just multiply the bases and add up the exponents.
9c^6*3c^6 = 27c^6+6 = 27c^12 <- answer
Answer:
2
Step-by-step explanation:
The first equation is that of a an ellipse. The second equation is that of a line.
Attached is the graphs of both of these equations.
<em>If you think about it, there can only be 2 possible ways of solutions (intersection points) of an ellipse and a line.</em>
<em>1. The line will not intersect the ellipse at all, so no solution</em>
<em>2. The line will intersect the ellipse at 2 points maximum</em>
<em />
So, we can clearly see from the reasoning that the maximum number of possible solutions would be 2. The graph attached confirms this as well.
