If you're not sure, begin by looking for any divisor that will divide into 24a^3c and 3a without leaving a remainder. Note that 3 is such a number, and a is another.
Factoring out 3a from 24a^3*c and 3a, we get 3a{8a^2*c, 1}
So the GCF is 3a.
Answer:
y = (x -5)² + 3.
Step-by-step explanation:
Given : parabola with a vertex at (5,3).
To find : Which equation has a graph that is a parabola.
Solution : We have given vertex at (5,3).
Vertex form of parabola : y = (x -h)² + k .
Where, (h ,k ) vertex .
Plug h = 5 , k= 3 in vertex form of parabola.
Equation :y = (x -5)² + 3.
Therefore, y = (x -5)² + 3.
Answer:
dodecagon
Step-by-step explanation:
Since y=5 is an asymptote, it means that y will approach 5 but never be 5. So you use (. Then, you see the function increasing from the asymptote so it would be (5, infinity) Choice C