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makvit [3.9K]
3 years ago
9

Just help please need to pass

Mathematics
2 answers:
Anni [7]3 years ago
7 0

Answer: \frac{1}{10}

Step-by-step explanation:

First, we need to find the common denominator

The easiest way to do this is by multiplying the two given denominators, which are 2 and 5.

2 × 5 = 10

So, our common denominator is 10. Then, multiply the numerators of the two fractions by 2 and 5. Here's why:

\frac{3*2}{5*2} = \frac{6}{10}         We multiplied the top and bottom by 2 to make sure our new fraction stays equivalent to the original fraction.

Do the same thing for the other one:

\frac{1*5}{2*5} = \frac{5}{10}

Finally, subtract the two fractions to find the difference between the two times:

\frac{6}{10} -\frac{5}{10} = \frac{1}{10}

The reason we used the common denominator is because we can only add or subtract fractions if they have the same denominator.

worty [1.4K]3 years ago
4 0
1/10 is the answer:)
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8 0
3 years ago
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almond37 [142]

Answer:

.92

Step-by-step explanation:

sin A = opp side/ hypotenuse

       

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3^2 +7^2 = AC ^2

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3 years ago
An album sells for $17.00 through an online music service. If the album is 20% off, and sales tax is 6%, what is the total price
V125BC [204]

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4 years ago
Convert 9ft -2 1/2in to inches
Mandarinka [93]

we know that


1 ft is equal to 12 in

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8 0
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Please Help! This is a trigonometry question.
liraira [26]
\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}


\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}

\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}

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\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}

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\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}

\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237


\large\textsf{I hope it helps.}


Tags: <em>trigonometry trig function cosecant csc double angle identity geometry</em>

</span>
8 0
4 years ago
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