The amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
<h3>What is compound interest?</h3>
Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-
![A=P[1+\dfrac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
a) The amount in the bank after 6 years if interest is compounded annually.
![A=P[1+\dfrac{r}{1}]^{t}\\\\\\A=6000[1+\dfrac{0.01}{1}]^{ 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B1%7D%5D%5E%7Bt%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B1%7D%5D%5E%7B%20%206%7D)
A= $6369
b) The amount in the bank after 6 years if interest is compounded quarterly.
![A=P[1+\dfrac{r}{4}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{4}]^{4\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B4%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B4%7D%5D%5E%7B4%5Ctimes%206%7D)
A= $6090
c ) The amount in the bank after 6 years if interest is compounded monthly.
![A=P[1+\dfrac{r}{12}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{12}]^{12\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B12%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B12%7D%5D%5E%7B12%5Ctimes%206%7D)
A=$6030
Hence the amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
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Aaron should use d..............o
Answer:
c
Step-by-step explanation:
Step-by-step explanation:
[1/2]^-2= 4
[1/3]^-2=9
[1/4]^-2=16
So sum is 4+9+16=29
Hope this helps you.
Answer: Since 1/3 can't be turned into a decimal, change .5 into 1/2. In order to subtract, the fractions need a common denominator. The least common denominator is 6. So 1/3 turns into 2/6, and 1/2 turns into 3/6. Now you need to take 9 3/6 minus 6 2/6. The answer is 3 1/6 gallons of water.
Step-by-step explanation: