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Nikitich [7]
3 years ago
7

The data set represents the ages of students, in years, attending a robotics club meeting. What is the median age of the student

s in the club?
13, 15, 12, 12, 11, 16, 11, 13, 14, 12
Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

12.5

Step-by-step explanation:

put them in order from least to greatest: 11, 11, 12, 12, 12, 13, 13, 14, 15, 16

the middle is 12 and 13 so you do 12+13 then divide by 2

to get 12.5

hope this helps

You might be interested in
Acertijo.
Cerrena [4.2K]

La edad de cada uno de los integrantes del acertijo es:

  • <u>Luisa = 3 años </u>
  • <u>Juan = 6 años </u>
  • <u>Carmen = 8 años</u>

<em>Cálculo por medio de ecuaciones y el </em><em>método de igualación</em>.

Haciendo uso de la información brindada en el ejercicio, se procede a formular variables con las cuales se calcularán las ecuaciones, por lo tanto:

  • <em>X = Edad de Luisa</em>
  • <em>Y = Edad de Juan</em>
  • <em>Z = Edad de Carmen</em>

Con el enunciado: <em>"Luisa es 3 años más joven que su hermano Juan"</em> se crea la primera ecuación:

  • 1. Y = X + 3

Con el enunciado: <em>"Su hermana Carmen es 2 años mayor que Juan"</em>, se crea la segunda ecuación:

  • 2. Z = Y + 2

Y con el enunciado: <em>"Juan tiene el doble de edad que Luisa"</em>, se crea la tercera ecuación:

  • 3. X = \frac{Y}{2}

Ahora, utilizando el método de igualación, se reemplaza la <em>tercera ecuación en la primera</em>:

  • Y = X + 3
  • Y = (\frac{Y}{2}) + 3

Y se procede a sumar:

  • Y = (\frac{Y}{2}) + 3
  • Y = \frac{Y+6}{2}

El dividendo se pasa al otro lado de la igualdad a multiplicar:

  • 2Y = Y + 6

Y la variable "Y" que está sumando, se pasa al otro lado de la igualdad a restar:

  • 2Y - Y = 6
  • <u>Y = 6</u>

Con el valor de Y (edad de Juan) <em>se calcula X con la tercera ecuación</em>:

  • X = \frac{Y}{2}
  • X = \frac{6}{2}
  • <u>X = 3</u>

Una vez calculado el valor de X (edad de Luisa), se procede a <em>calcular el valor de Z con la segunda ecuación</em>:

  • Z = Y + 2
  • Z = 6 + 2
  • <u>Z = 8</u>

Por lo tanto, se calcula que <u>la edad de Luisa es 3 años, la edad de Juan es 6 años y la edad de Carmen es 8 años</u>.

Más información sobre ecuaciones:

brainly.com/question/15415929?referrer=searchResults

8 0
3 years ago
Heather is going to order a pizza and can choose from a thin or a thick crust, white or red sauce, and one of either mushrooms,
STALIN [3.7K]
You can choose A. It’s a pretty solid choice
7 0
3 years ago
Read 2 more answers
What’s the given m ABC = 70 and m ADC = 46
uysha [10]

Answer:

Step-by-step explanation:

Properties of a kite;

1). A kite has one pair of equal angles.

2). A kite has two pairs of adjacent sides.

3). Diagonals of a kite intersect at 90°.

4). Kite has at least one diagonal that bisects the opposite angles.

It's given in the question,

m∠ABC = 70° and m∠ADC = 46°

By the property number -4,

m∠2 = m∠3 = \frac{70}{2} = 35°

m∠8 = m∠9 = \frac{46}{2} = 23°

By the property number - 3,

m∠4 = 90°

By the property of interior angles in a triangle,

m∠3 + m∠4 + m∠5 = 180°

35° + 90° + m∠5 = 180°

125° + m∠5 = 180°

m∠5 = 55°

Similarly, m∠1 + m∠2 + 90° = 180°

m∠1 + 35° + 90° = 180°

m∠1 = 55°

Now m∠6 + 90° + m∠8 = 180°

m∠6 + 90° + 23° = 180°

m∠6 = 180 - 113 = 67°

Therefore, m∠6 = m∠7 = 67°

3 0
3 years ago
What should be the first step in solving 13 y − 14 = 42?
AveGali [126]

Answer:

The first step should be adding 14 to both sides of the equation.

Step-by-step explanation:

14 must be added on both sides of the equation to get 13y by itself. The ultimate goal is to get y by itself if we are solving for y.

Once 14 is added on both sides, you'll get:

13y = 56.

Then 13 would be divided from both sides.

y = 4.3

8 0
3 years ago
Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles.
diamong [38]

Answer:

A.

\dfrac{6}{55}

B.

\dfrac{6}{55}

C.

\dfrac{4}{165}

Step-by-step explanation:

Dustin has a bag of marbles with 4 blue marbles, 4 white marbles, and 3 red marbles. There are 11 marbles in total.

A. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is red marble is

\dfrac{3}{10}

The probability that the first marble drawn is blue and the second is red is

\dfrac{4}{11}\cdot \dfrac{3}{10}=\dfrac{12}{110}=\dfrac{6}{55}

B. The probability that the first marble drawn is red marble is

\dfrac{3}{11},

the probability that the second marble drawn is white marble is

\dfrac{4}{10}

The probability that the first marble drawn is red and the second is white is

\dfrac{3}{11}\cdot \dfrac{4}{10}=\dfrac{12}{110}=\dfrac{6}{55}

C. The probability that the first marble drawn is blue marble is

\dfrac{4}{11},

the probability that the second marble drawn is blue marble is

\dfrac{3}{10},

the probability that the third marble drawn is blue marble is

\dfrac{2}{9},

The probability that the first, second and third marbles drawn are blue is

\dfrac{4}{11}\cdot \dfrac{3}{10}\cdot \dfrac{2}{9}=\dfrac{24}{990}=\dfrac{4}{165}

8 0
3 years ago
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