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tatuchka [14]
4 years ago
6

6/2=4/p= Can u help me with this math problem

Mathematics
1 answer:
vodomira [7]4 years ago
5 0
I hope this helps you


6/2=4/p


3=4/p


p=4/3

p=1,333...
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alexandr1967 [171]
Using the picture:

Between (-3, -4) and (5, -4) is:
The difference is in the x units:  5 - (-3) = 5 + 3 = 8

Between (5, 2) and (5, -4) is:
The difference is in the y units:  2 - (-4) = 2 + 4 = 6

We know the shape is a right angled triangle:

By applying Pythagoras' Theorem:

let the hypotenuse be x:

x² = 6² + 8²

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Take square root of both sides

√x²  = √100

x = 10

Distance between the 2 points = 10 units.

Option D. 
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A bowl contains 10 red marbles and 10 green marbles. A woman selects marbles at random without looking at them. Assume that the
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blondinia [14]

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3 years ago
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrad
SIZIF [17.4K]

Answer:

50kg de café torrado

30kg de café arábico

Step-by-step explanation:

Queremos obtener un total de 80kg de café molido.

Se utilizarán:

Café arábico, que cuesta $18 el kg

Café torrado, que cuesta $10 el kg

Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.

Ok, primero debemos definir las variables:

Definamos:

x = cantidad de café arábico usado

y = cantidad de café torrado usado.

Entonces, como la mezcla deberá tener 80kg en total, tenemos:

x + y = 80kg

Y el costo total de esta mezcla será:

x*$18 + y*$10

Si lo dividimos por el peso total, tendremos el costo por kilo, que es:

(x*$18 + y*$10)/80kg

Y queremos que esto sea igual a $13, entonces tenemos la ecuación

(x*$18 + y*$10)/80kg = $13

Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:

x + y = 80kg

(x*$18 + y*$10) = $13*80kg

(donde reescribimos levemente la segunda ecuación)

Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.

Aislemos x en la primera:

x = 80kg - y

Ahora reemplazamos esto en la otra ecuación:

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(( 80kg - y)*$18 + y*$10) = $13*80kg

Ahora podemos resolver esto para la variable y:

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$18*80kg - $13*80kg = $18*y - $10*y

($18 - $13)*80kg = ($18 - $10)*y

$5*80kg = $8*y

($5*80kg)/$8 = y

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Se usan 50kg de café torrado.

y como:

x + y = 80kg

x = 80kg - y

x = 80kg - 50kg = 30kg

Entonces los 30kg restantes serán de café arábico.

y la estrategia utilizada fue el remplazo de variables.

6 0
3 years ago
How many solutions does this equation have? 9x + 27 = 27
Nikolay [14]
Move all the terms that don’t contain x to the right side and solve.
x=0
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