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3 years ago

Why do you think solar panels would work well in space

Physics

2 answers:

julsineya [31]3 years ago

5 0

Answer:

Solar panel equipped, energy transmitting satellites collect high intensity, uninterrupted solar radiation by using giant mirrors to reflect huge amounts of solar rays onto smaller solar collectors.

Explanation:

algol [13]3 years ago

3 0

They work well in space because they receive the full amount of sunlight without any atmosphere or clouds getting in the way. This assumes that objects such as other planets don't cover up the sun. Also, the spacecraft can't be too far away from the sun. If the spacecraft was at Pluto for instance, then the sun is not as effective as compared to at Mars.

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GarryVolchara [31]

Explanation:

Given that,

The pilot directs the aircraft to fly due north at 600km/h.

A side-wind blows at 100km/h towards the east.

We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :

$v=\sqrt{600^2+100^2} \\\\v=608.27\ m/s$

For direction,

$\tan\theta=\dfrac{600}{100}\\\\\tan\theta=6\\\\\theta=\tan^{-1}(6)\\\\\theta=80.53^{\circ}$

So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.

7 0

3 years ago

| The electric field 5.0 cm from a very long charged wire is (2000 N/C, toward the wire). What is the charge (in nC) on a 1.0-cm

Serggg [28]

Answer:

The charge is 0.056 nC.

Explanation:

Given that,

Electric field = 2000 N/C

Distance = 5.0 cm

We need to calculate the charge density

Using formula of charge density

$E=\dfrac{\lambda}{2\pi\times\epsilon_{0}r}$

$\lambda=2\pi\times\epsilon_{0}\times r\times E$

Put the value into the formula

$\lambda=2\pi\times8.85\times10^{-12}\times5.0\times10^{-2}\times2000$

$\lambda=5.56\times10^{-9}\ C/m$

We need to calculate the charge in 1.0 cm

Using formula of charge

$Charge = \lambda\times\text{length of segment}$

$Charge =5.56\times10^{-9}\times1.0\times10^{-2}$

$Charge=0.056\times10^{-9}\ C$

$Charge=0.056\ nC$

Hence, The charge is 0.056 nC.

3 0

3 years ago

How does the thickness of wood affect its stability

Law Incorporation [45]

Answer:

Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.

7 0

3 years ago

n noisy factory environments, it's possible to use a loudspeaker to cancel persistent low-frequency machine noise at the positio

lys-0071 [83]

Answer:

7.888m

Explanation:

Given:

frequency 'f'= 90Hz

velocity of the sound 'v' = 340 m /sec

The wavelength of the wave is given by,

λ= v/f => 340/90

λ= 3.777m

The destructive interference condition is givn by

Δd= $(m+\frac{1}{2} )$ λ

where, m=0,1,2,3,..

m=0, for minimum destructive interference

Δd= $(0+\frac{1}{2} )$ x 3.777

Δd=1.888

Therefore, the required distance is

$d_f$ = $d_i$ + Δd => 6 + 1.888

$d_f$ = 7.888m

Thus, So the speaker should be placed at 7.888 m

4 0

3 years ago

A 50 kg car is pushed so that it speeds up from 20 m/s to 50 m/s in 3 seconds. What is the force acting on the car?

egoroff_w [7]

Answer:

A. 500 N

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (50 m/s − 20 m/s) / 3 s

a = 10 m/s²

Force is mass times acceleration.

F = ma

F = (50 kg) (10 m/s²)

F = 500 N

3 0

3 years ago