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marta [7]
3 years ago
7

An unknown mass is on a flat frictionless surface and a 2 kg object is attached to it with a string going over pulleyt mounted t

o the end of the table. Acceleration of the 2 kg object is 1.8 m/s^2. What is the mass of the object?
Physics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

Explanation:

F=ma

F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so

F = 2kg*(9.8 m/s^2) = 19.6 N

Now use this force to determine the mass of the object on the table:

F=ma

19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)

m = 10.89 kg

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A small plastic ball with a mass of 7.00 10-3 kg and with a charge of +0.155 µC is suspended from an insulating thread and hangs
adell [148]

Answer:

the magnitude of the charge Q on each plate is 3.053 *10^{-8} \ C

Explanation:

Given that :

mass (m) = 7.00 *10 ^{-3} \ kg

charge (q) = +0.155 µC = +0.155 *10^{-6}\ C

angle \theta = 30^0 \ C

Area A on each plate = 0.0135 m²

From the diagram below;

tan \ \theta = \frac{Eq}{mg}    ----- equation (1)

Also by using Gauss Law ;

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Q = \epsilon_0EA     ----- equation (2)

Combination equation 1 and 2 together ; we have

Q = \frac{\epsilon_0\ * \ m\ *\ g \ \ * \ tan \theta \ * \ A}{q}

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8 0
3 years ago
You walk 20 m north then 30 m west for a total timer four minutes what is the magnitude of your average velocity in (m/s)
Shalnov [3]

Answer:

The average velocity is 0.15 m/s

Explanation:

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distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} = \sqrt{(-30)^2+20^2} =\sqrt{1300} \approx 36.06\,\,m

Then the magnitude of the average velocity can be estimated via the quotient between distance divided time, but since the units required are meters per second, we first convert the four minute time into seconds: 4 * 60 = 240 seconds.

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v_{ave}=\frac{distance}{time} =\frac{36.06}{240} =0.15\,\,m/s

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4 years ago
In a certain oscillating LC circuit, the total energy is converted from electrical energy in the capacitor to magnetic energy in
aleksandrvk [35]

Answer:

A = 5.6μs

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