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Kryger [21]
3 years ago
11

Find questions attached.Show workings.You can skip question (a)​

Mathematics
2 answers:
rusak2 [61]3 years ago
6 0

<u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>4</u><u>0</u><u>°</u>

Answer:

Solution given:

In triangle BCE

<C+<B+<E=180°[sum of interior angle of a triangle]

<C+60°+x°=180°

<C=180°-60°-x°

<C=120°-x°

again

<A=<C[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]

2x=120-x

2x+x=120°

3x°=120°

x°=120°/3°

x°=40°

Veseljchak [2.6K]3 years ago
4 0

Now we have to,

find the required value of x.

Then in ∆ BCE,

By sum of interior angle of a triangle.

→ <C+<B+<E = 180°

→ <C+60°+x = 180°

→ <C = 180-60-x

→ <C = 120-x

Now by the exterior angle of,

A cyclic quadrilateral is equal to the opposite interior angle.

→ <A = <C

→ 2x = 120-x

→ 2x+x = 120

→ 3x = 120

→ x = 120/3

→ x = 40°

Hence, 40° is the value of x.

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