Find questions attached.Show workings.You can skip question (a)
2 answers:
<u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>4</u><u>0</u><u>°</u>
Answer:
Solution given:
In triangle BCE
<C+<B+<E=180°[sum of interior angle of a triangle]
<C+60°+x°=180°
<C=180°-60°-x°
<C=120°-x°
again
<A=<C[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]
2x=120-x
2x+x=120°
3x°=120°
x°=120°/3°
x°=40°
Now we have to,
find the required value of x.
Then in ∆ BCE,
By sum of interior angle of a triangle.
→ <C+<B+<E = 180°
→ <C+60°+x = 180°
→ <C = 180-60-x
→ <C = 120-x
Now by the exterior angle of,
A cyclic quadrilateral is equal to the opposite interior angle.
→ <A = <C
→ 2x = 120-x
→ 2x+x = 120
→ 3x = 120
→ x = 120/3
→ x = 40°
Hence, 40° is the value of x.
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