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Kryger [21]
3 years ago
11

Find questions attached.Show workings.You can skip question (a)​

Mathematics
2 answers:
rusak2 [61]3 years ago
6 0

<u>The</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>is</u><u> </u><u>4</u><u>0</u><u>°</u>

Answer:

Solution given:

In triangle BCE

<C+<B+<E=180°[sum of interior angle of a triangle]

<C+60°+x°=180°

<C=180°-60°-x°

<C=120°-x°

again

<A=<C[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]

2x=120-x

2x+x=120°

3x°=120°

x°=120°/3°

x°=40°

Veseljchak [2.6K]3 years ago
4 0

Now we have to,

find the required value of x.

Then in ∆ BCE,

By sum of interior angle of a triangle.

→ <C+<B+<E = 180°

→ <C+60°+x = 180°

→ <C = 180-60-x

→ <C = 120-x

Now by the exterior angle of,

A cyclic quadrilateral is equal to the opposite interior angle.

→ <A = <C

→ 2x = 120-x

→ 2x+x = 120

→ 3x = 120

→ x = 120/3

→ x = 40°

Hence, 40° is the value of x.

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6 0
3 years ago
Use the equation, 16^2x=32^(x+3), to complete the following problems.
olga55 [171]

Answer:

x = 5

Step-by-step explanation:

2⁴(2x) = 2⁵(x + 3)

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cancel out the 2

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8 0
3 years ago
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w
pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, the circle is centered at the origin, hence (x_0, y_0) = (0,0).

The circle contains the point (-13,0), hence the radius is found as follows:

x^2 + y^2 = r^2

(-13)^2 + 0^2 = t^2

r^2 = 169

Hence the equation is:

x^2 + y^2 = 169

Then, we test if point (√5, 12) is on the circle:

x^2 + y^2 = 169

(\sqrt{5})^2 + 12^2 = 169

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0
3 years ago
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