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Xelga [282]
3 years ago
13

Identify the range of the following data set. 20, 22, 58, 48, 32, 20, 23

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

the correct answer is 38

andrew-mc [135]3 years ago
3 0
The answer is 38 since range=high - low = 58-20
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What is a divided 9= -4
sladkih [1.3K]
Do you mean what is 9 divided by negative 4 or ?

Sorry, I'm just confused.
3 0
3 years ago
Hi someone please help. 5TH GRADE HELP
Effectus [21]

Answer:

10

Step-by-step explanation:

2 [32 - (4 - 1)³]

2[32 - (3)³]

2[32 - 27]

2[5]

10

4 0
3 years ago
The two-way table shows the number of sport utility vehicles with certain features for sale at the car lot. a 4-column table has
Mekhanik [1.2K]

The probability that a randomly selected car with no 4-wheel drive has third-row seats is given by: Option B: 0.4

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

<h3>What is chain rule in probability?</h3>

For two events A and B, by chain rule, we have:

P(A \cap B) = P(B)P(A|B) = P(A)P(B|A)

where P(A|B) is probability of occurrence of A given that B already occurred.

For this case, the table given is:

Entries                          4-wheel drive        No 4-wheel drive        Total

Third Row Seats                  18                                12                        30

No Third Row Seats             7                                28                        35

Total                                     25                               40                        65

Let we take

A = event that a randomly selected car has no-4 wheel drive

B = event that a randomly selected car has third row seats

The total ways a car can be selected = 65 = n(S)

Total ways A can happen = n(A) = 40 (from the table).

Similarly, n(B) = 30

P(A) = n(A)/n(S) = 40/65

P(B) = n(B)/n(S) = 30/65

P(A∩B) = n(A∩B)/n(S) = 12/65

As by chain rule, we have:

P(A∩B) = P(A)P(B|A) = P(B)P(A|B)

We need P( A randomly selected car has three seats given that the selected car is with no 4-wheel drive)

which is symbolically P( B | A)

Thus, we use: P(A∩B) = P(A)P(B|A)

or

12/65 = (30/65)(P(B|A))\\\dfrac{12/65}{30/65} = P(B|A)\\\\P(B|A) = \dfrac{12}{30} = \dfrac{2}{5} = 0.4

Thus, the probability that a randomly selected car with no 4-wheel drive has third-row seats is given by: Option B: 0.4

Learn more about probability here:

brainly.com/question/1210781

3 0
2 years ago
If y is directly proportional to x, and y = 5 when x = 2, what is the value of y when x = 6?
Korolek [52]

it could be 2.2 because every 5 you get 2 so it would be 10 and 4 so when y=6 then x should be 2.2.

3 0
3 years ago
Read 2 more answers
-5/x= 2/6<br><br> those are fractions btw
irina [24]
Hope it helps you x=-15

6 0
3 years ago
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