Question

Write the quadratic equation in standard form. (x - 3) 2 = 0

Answer 1

(x - 3)^2 = 0
(x - 3)(x - 3) = 0
x^2 - 3x - 3x + 9 = 0
x^2 - 6x + 9 = 0 <===

Answer 2

Answer:

$x^{2} -6x+9$

Step-by-step explanation:

This binomial can be solved by the perfect square binomial method. Its standard form is:

$(a-b)^{2} = a^{2} -2ab+b^{2}$

In this way, substituting

$a=x; b=3$

$(x-3)^{2} = x^{2} -2(x)(3)+(3)^{2} = x^{2} -6x+9$