How to solve b 2 + 5b -35 = 3b

A car is driven 440 miles in 11 hours. What is the rate in miles per hour?

nikklg [1K]

Answer:

40 Mph

Step-by-step explanation:

440/11 is equal to 40

5 0

3 years ago

Read 2 more answers

How do I solve this equation?

svlad2 [7]

The answer is option three(photo for step by step)

5 0

3 years ago

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Factorise 9w² - 100

ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

In this question, the expression $(9\, w^{2} - 100)$ is the difference between two terms: $9\, w^{2}$ and $100$ .

$9\, w^{2}$ is the square of $3\, w$ . That is: $(3\, w)^{2} = 9\, w^{2}$ .
On the other hand, $10^{2} = 100$ .

Hence:

$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

Apply the fact that $a^{2} - b^{2} = (a - b) \, (a + b)$ to factorize this expression. (In this case, $a = 3\, w$ whereas $b = 10$ .)

$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

8 0

3 years ago

A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t

Katyanochek1 [597]

The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability) is the opposite of (no car probability) In this case, the easier way is
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability)
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability = (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120

3 0

3 years ago

How do I get to the answer? (3 x n) + 4 = 32/2 What is the value of n?

charle [14.2K]

If you simplify what's in the bracket, you get 3n

=(3n)+4=32/2
=3n+4= 32/2(here we can either crossmultiply or equate)
3n+4-4=32/2-4(subtract 4 from both sides)
3n=32/2-4
3n=24/2
3n=12
3n=12(divide both sides by the coefficient of the unknown)
3n/3=12/3
n=4

3 0

3 years ago