Answer:
The answer is C. 16x² - 56xy + 49y²
Step-by-step explanation:
A perfect square trinomial is the result of a squared binomial, the perfect square trinomial would be a² + 2ab + b², as that is what you get when you expand the brackets.
Answer:
1017.36
Step-by-step explanation:
9times 36=324
324 times pi =1017.36
Answer:
∠2 and ∠5
Step-by-step explanation:
we know that
<u>Alternate Exterior Angles</u> are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal
In this problem
∠12 and ∠2 are alternate exterior angles
∠12 and ∠5 are alternate exterior angles
therefore
∠2 and ∠5 are each separately alternate exterior angles with ∠12
<h3><u>Question:</u></h3>
There are 3900 workers in the three main buildings downtown. Twice as many people work in the largest building as in the smallest of the three. There are 500 more workers in the second-largest building than in the smallest building. How many workers are in each building?
<h3><u>Answer:</u></h3>
There are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building
<h3><u>Solution:</u></h3>
Let "b" be the number of workers in smallest building
Given that Twice as many people work in the largest building as in the smallest of the three
number of workers in largest building = 2b
Given that There are 500 more workers in the second-largest building than in the smallest building
Number of workers in second largest building = 500 + b
Given that there are 3900 workers in 3 buildings
b + 2b + 500 + b = 3900
4b + 500 = 3900
4b = 3900 - 500
4b = 3400
b = 850
Thus there are 850 workers in smallest building
workers in largest building = 2b = 2(850) = 1700
workers in second largest building = 500 + b = 500 + 850 = 1350
Thus there are 850 workers in smallest building and 1700 workers in largest building and 1350 workers in second largest building
Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
