Ask question

Ask question

All categories

3 years ago

6

Erika and Bradley want to hike the big cypress trail. they will hike a total of 75 miles. If Erika and Bradley plan to hike for

12 days. how many miles will they hike each day?

2 answers:

lakkis [162]3 years ago

7 0

6.25 miles per day

You have to divide the total miles (75) by the number of days (12).

ahrayia [7]3 years ago

4 0

They will hike 6.25 miles a day

You might be interested in

What is .75 rounded to the nearest thousandth?

Ymorist [56]

.75 Rounded to the nearest thousandth would be 0.750

5 0

3 years ago

Help please fast the format is Y-____=_____(x - ____) and i need the actual answer

mojhsa [17]

9514 1404 393

Answer:

y -195 = 15(x -9)
$60

Step-by-step explanation:

The form of the equation you are given is called "point-slope" form. The "slope" in this case is the per-hour fee. The point is (9 h, $195). Point-slope form generally looks like this:

y -k = m(x -h) . . . . . line with slope m through point (h, k)

Here, you have m=15, (h, k) = (9, 195), so the equation looks like ...

y -195 = 15(x -9)

__

The "one-time fee" is the cost when hours are zero.

y -195 = 15(0 -9)

y = 195 -9(15) = 60 . . . . add 195 to both sides, and evaluate

The one-time fee is $60.

5 0

2 years ago

Which expressions are equivalent to (5g+3h+4) •2

timama [110]

Step-by-step explanation:

Unfortunately you didn’t provide the expressions to chose from

however, we can write :

(5g+3h+4) •2 = 2*5g + 2*3h + 2*4 (using distributive property)

= 10g + 6h + 8.

5 0

3 years ago

-5a to the second power-7a

kakasveta [241]

-5a^2 - 7a = -a x (5a + 7)
let me know if you have any other questions
:)

7 0

3 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago