Trey takes the angle shown, places the point of his compass on S, and draws an arc with an arbitrary radius intersecting the ray
s of the angle at P and R. Trey claims that as long as he draws two more arcs by placing the needle of his compass on P and then on R, drawing a ray from S through the point at which the arcs intersect, he will be able to bisect ∠S. Is Trey correct?
A. Trey is correct. Since the initial arc was drawn with the point of the compass on S, RS=PS.
B. Trey is not necessarily correct. He will need to ensure that the compass width remains the same for each arc drawn from P and R.
C. Trey is correct. Since the compass is placed on the points P and R to draw the remaining two arcs, the ray drawn through their intersection will bisect the angle.
D. Trey is not necessarily correct. He will need to ensure that the distance from S to P and the distance from S to R are equal.
A. Trey is correct. Since the initial arc was drawn with the point of the compass on S, RS=PS.
B. Trey is not necessarily correct. He will need to ensure that the compass width remains the same for each arc drawn from P and R.
C. Trey is correct. Since the compass is placed on the points P and R to draw the remaining two arcs, the ray drawn through their intersection will bisect the angle.
D. Trey is not necessarily correct. He will need to ensure that the distance from S to P and the distance from S to R are equal.
2 answers:
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