Answer:
The minimum sample size that should be taken is 62.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
If we want to be 90% confident that the sample mean is within 1 word per minute of the true population mean, what is the minimum sample size that should be taken
This is n when 
. So
The minimum sample size that should be taken is 62.
The answer is 4 inches. This is because the scale is 1 inch=3 feet. And when doing 12ft divided by 3ft you get 4. The 4 then represents 4 inches. Hope it helps :)
1 kg--> 0.264 kg fat
:. 12.5 kg--> (0.264*12.5) 3.3 kg fat
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A^2+b^2= c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c
The percentage of the radioactive isotope left is 25.0000%.
<h3>What is the half life?</h3>
The half life of a radioactive isotope is the time that will elapse before only half of the number of original isotopes will remain.
Now;
We are told that;
Half life (t1/2) = 55 days
Time taken (t) = 115 days
Ratio of isotope remaining = N/No
Thus;
N/No = (1/2)^t/t1/2
N/No = (1/2)^115/55
N/No = (1/2)^2
N/No =1/4
Hence, the percentage = 1/4 * 100/1 = 25.0000%
Learn more about half life of an isotope:brainly.com/question/16387602
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