I believe this question logically tells us to find the value of w. The two equations are already equated. Since there is 1 unknown and 1 equation, the system is solvable. The solution is as follows:
5/(6w+21) = -1/3(2w - 9)
5/(6w+21) = -1/(6w - 27)
Cross multiplying the terms:
5(6w - 27) = -1(6w +21)
30w - 135 = -6w - 21
30w + 6w = -21 + 135 = 114
36w = 114
w = 114/36
w = 19/6 or 3.167
Answer:
19
Step-by-step explanation:
1-(-18)
=1+18
=19
Awnser:
1/2 as m, and -3 as b
Step-by-step explanation:
To find the equation of any line, you use the formula: mx+b=y, where m is the slope, y is the y coordinate, b is the y intercept, and x is the x coordinate. However, it only asks for b and m.
You'll need to first find 2 points.
I chose: (6,0) and (0,-3).
The formula to find the slope is: y2-y1/x2-x1.
0-(-3)/6-0
0+3/6
3/6
1/2
Now we need to find the y intercept. However, the graph already tells you what it is. The y intercept always has to have 0 as x.
So the awnser is 1/2 as m, and -3 as b.
Answer: Mean = 52.8 mins
Step-by-step explanation:
We have lapses of 30 minutes, so we can write the average for each, this means that:
0 < t < 30 can be averaged to the middle of the range: 15 min.
Doing this, we have that:
7 students 15 min
27 students 45 min
12 students 75 min
4 students 105 min.
Now we can calculate the mean:
mean = (x1*n1 + x2*n2 + ...)/N
where x1 is the amount of time 1, and n1 is the number of students associated to that time and so on. N is the total number of students
Mean = (7*15min + 27*45min + 12*75min + 4*105min)/(7 + 27 + 12 + 4)
Mean = 52.8 mins
