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AfilCa [17]
3 years ago
11

What is 4×3^2-3+5×2=

Mathematics
1 answer:
stepladder [879]3 years ago
3 0
86 opposite of it so it would be87
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Part (1) : The solution is 729

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is 3^{2} \cdot3^{4}

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$, we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

3^{2} \cdot3^{4}=3^6=729

Thus, the simplified value of the expression is 729

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$, we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

\frac{1}{2^4x^8}

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$, we have,

\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}

Adding the powers, we get,

\frac{2x^{2}y^{-1}z^{-7}}{3}

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$, we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0
4 years ago
Which table shows a function whose range has exactly three elements
Rudik [331]
<h2>Answer:</h2>

The table which shows that a function's range has exactly three elements is:

         x      y

         3      8

        4      6

        5      12

        6       8

<h2>Step-by-step explanation:</h2>

<u>Domain of a function--</u>

The domain of a function is the set of all the x-values i.e. the value of the independent variable for which a function is defined.

<u>Range of a function--</u>

It is the set of all the y-value or the values which are obtained by the independent variable i.e. the values obtained by the function in it's defined domain.

a)

     x      y

     1      4

     2      4

     3       4

Domain: {1,2,3}

Range: {4}

Hence, the range has a single element.

b)

     x      y

     3      8

     4      6

     5      12

     6       8

Domain: {3,4,5,6}

Range: {6,8,12}

Hence, the range has three element.

c)

     x      y

     0     5

     2      9

     0      15

This relation is not a function.

because 0 has two images.

0 is mapped to 5 and 0 is mapped to 15.

d)

     x      y

     1      4

     3     2

    5      1  

    3      4

This relation is not a function.

because 3 has two images.

3 is mapped to 2 in the ordered pair (3,2) and 3 is mapped to 4 in the ordered pair (3,4)

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