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Nikitich [7]
3 years ago
11

There are 48 students in a certain class, 25% of this are girls, How many boys are in the class?

Mathematics
1 answer:
miskamm [114]3 years ago
4 0

Answer:

There are 36 boys

Step-by-step explanation:

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Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma
scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

315+213-123 =405

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = 500-405 =95

Exactly one course is either math or economics - both

= 405-123 = 282

3 0
4 years ago
Write as a fraction and simplify. (use the symbol / in your answer).<br> 0.878787.....
Alika [10]

Answer:

.878787.. to a fraction is 29/33

Step-by-step explanation:

\frac{(0.87*100)-0}{99} = 87/99

Simplify 87/99, which is 29/33

3 0
3 years ago
Did I get this right?
wel

Yes hope it helps!!!!!!!!

4 0
3 years ago
SUSAN AND TEO PLAY SOCCER. SUSANS TEAM PLAYS EVERY FIVE DAYS. TEO'S TEAM PLAYS EVERY SIX DAYS. WHEN WILL THE TWO TEAMS PLAY TOGE
salantis [7]
Yes the answer is 30.
3 0
3 years ago
Read 2 more answers
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
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