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aleksley [76]
3 years ago
7

What is the mode of the data?

Mathematics
1 answer:
Lesechka [4]3 years ago
7 0

Answer:

0, 5, and 9

Step-by-step explanation:

Mode is (are) the number(s) that is (are) repeated the most times. Lets rewrite the numbers in clusters to see which number(s) are repeated the most times:

0 0 0

1 1

2 2

3 3

5 5 5

6

9 9 9

The numbers 0, 5, and 9 are repeated 3 times each. So these three numbers are the mode.

Hope it helps!

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Which is the correct net of the prism and what is the surface area of the prism?
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It will be Net A and the S. A. = 12*14 + 5*14 + 2(0.5*5*12) + 14*13 = 480

The correct option is  the second one.
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Please help out with this geometry homework I was assigned. And what formula do I use?
lozanna [386]

Answer:

V_{cone}   \approx 1,178.97 \:  {in}^{3}

Step-by-step explanation:

Diameter of cone = 16 in

Radius of cone r = 16/2 = 8 in

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V_{cone}  =  \frac{1}{3} \pi {r}^{2}h \\  \\  V_{cone}  =  \frac{1}{3}  \times 3.14 \times  {(8)}^{2} \times 17.6 \\  \\   V_{cone}  =  \frac{1}{3}  \times 3,536.896 \\  \\  V_{cone}  =  1,178.96533 \\  \\  V_{cone}   \approx 1,178.97 \:  {in}^{3}  \\

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3 years ago
A bag contains 72 toffees. How many toffees can be stored in 122 such bags? Estimate the number of toffees to nearest tens.
d1i1m1o1n [39]
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5 0
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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.3. (Round your ans
Maurinko [17]

Answer:

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 50

Standard Deviation, σ = 1.3

Sample size, n = 12

We are given that the distribution of hardness of pins is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{1.3}{\sqrt{12}} = 0.3753

P(sample mean hardness for a random sample of 12 pins is at least 51)

P( x \geq 51) = P( z \geq \displaystyle\frac{51 - 50}{0.3753}) = P(z \geq 2.6645)

= 1 - P(z < 2.6645)

Calculation the value from standard normal z table, we have,  

P(x \geq 51) = 1 - 0.9961= 0.0039

0.0039 is the probability that the sample mean hardness for a random sample of 12 pins is at least 51.

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3 years ago
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