Answer:
The solution for the system of equations is
x=2,y=−2
Explanation:
4x−3y=14.....equation (1)
y=−3x+4.....equation (2)
Solving by substitution
Substituting equation 2 in equation 1
4x−3⋅(−3x+4)=14
4x+9x−12=14
13x=14+12
13x=26
x=2
Finding y by substituting x in equation 1
4x−3y=14
4⋅2−3y=14
8−3y=14
8−14=3y
3y=−6
y=−2
3x-13=2
move -13 to the other side
sign changes from -13 to +13
3x-13+13=2+13
3x=2+13
3x=15
divide both sides by 3 to get x by itself
3x/3=15/3
cross out 3 and 3, divide by 3 and then becomes 1*1*x=x
x=15/3
x=5
answer:
x=5
Alright, so since anything can be squared, the domain is (-inf, inf)
B is correct as -4 is smaller than 7
d is correct as -30 is smaller than -18
e is correct as -3 is bigger than -8
