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svet-max [94.6K]
3 years ago
12

I need help and btw you can pick multiple answers

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0
The answer is angle two!!
victus00 [196]3 years ago
5 0

Answer:

i know for a fact angle two is one of the answers.

Step-by-step explanation:

A complementary angle is where two angles create a 90 degree angle.

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Amy buys two shirts. One shirt costs $12.95 and the other costs $15.98. How much money does Amy spend altogether
shtirl [24]

Answer:

$28.93

Step-by-step explanation:

 12.95+15.98 = $28.93

4 0
3 years ago
Read 2 more answers
A box of cereal states that there are 87 calories in a 3​-4cup serving. What is the unit rate for calories per​ cup? How many ca
riadik2000 [5.3K]

Answer: for 2 cups, There are 232 Calories.

Step-by-step explanation:

Step 1

Let the calories in one cup be represented as C

 Therefore

3/4 x C = 87 calories

C = 87 X 4 / 3 = 116

unit rate is 116 calories per cup.

Step 2- Solving the number of calories in 2 cups

1 cup serving = 116 calories

2 cups servings = 116 x 2= 232 calories

3 0
3 years ago
At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
The director of a state agency believes that the average starting salary for clerical employees in the state is less than $30,00
ss7ja [257]

Answer:

The test statistics is   z = -1  

Step-by-step explanation:

From the question we are told that

   The sample size is  n  =  100

  The null hypothesis  is  H_o : \mu = \$30000

   The alternative hypothesis is  H_a  :  \mu  < \$ 30000

   The sample mean is  \= x  = \$29,750

    The standard deviation is  \sigma  = \$2,500

    The level of significance is  \alpha =0.05

Generally the test statistics is mathematically represented as

        z = \frac{\= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }

=>      z = \frac{29750 - 30000 }{ \frac{ 2500}{ \sqrt{100} } }

=>      z = -1    

7 0
3 years ago
5/6-1/8 Solve by finding a common denominator<br><br> A)30/48<br> B)34/48<br> C)38/48<br> D)42/48
GrogVix [38]

Answer:

  B)  34/48

Step-by-step explanation:

The easiest common denominator to find is the product of the denominators you have.

__

The difference is ...

  \dfrac{5}{6}-\dfrac{1}{8}=\dfrac{5}{6}\cdot\dfrac{8}{8}-\dfrac{1}{8}\cdot\dfrac{6}{6}\\\\=\dfrac{40-6}{48}=\boxed{\dfrac{34}{48}}

__

<em>Additional comment</em>

The difference numerator and denominator have a common factor of 2, so can be reduced to 17/24. The denominator 24 could have been used as the common denominator from the start.

  5/6 -1/8 = 20/24 -3/24 = 17/24 . . . . reduced result

__

Using the <em>least common denominator</em> does not always result in a reduced sum or difference. If some other denominator is used (as here), then you can be assured that the result will need to be reduced to get to lowest terms.

8 0
2 years ago
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