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3 years ago

What is the product? (y^2)(2x^3+5)(x^2-4x-9)

Mathematics

1 answer:

Sloan [31]3 years ago

8 0

Answer:

2x5y2−8x4y2−18x3y2+5x2y2−20xy2−45y2

Step-by-step explanation:

y2(2x3+5)(x2−4x−9)

=(y2(2x3+5))(x2+−4x+−9)

=(y2(2x3+5))(x2)+(y2(2x3+5))(−4x)+(y2(2x3+5))(−9)

=2x5y2+5x2y2−8x4y2−20xy2−18x3y2−45y2

=2x5y2−8x4y2−18x3y2+5x2y2−20xy2−45y2

<em>Hope this helps! :)</em>

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write the logarithm as a sum or difference of logarithms. simplify each term as much as possible. log4(6ab)

Dominik [7]

The logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

<h3>Simplifying Logarithms</h3>

From the question, we are to write the given logarithm expression as a sum or difference of logarithms

The given logarithm is

$log_{4 }6ab$

This can be written as

$log_{4 }6 \times a \times b$

From one of the rules of logarithm, we have that

$log_{x }yz= log_{x }y + log_{x }z$

Thus,

$log_{4 }6 \times a \times b$ becomes

$log_{4 }6 + log_{4 }a + log_{4 }b$

This can be further simplified into

$log_{4 }3 \times 2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + log_{4 }2 + log_{4 }a + log_{4 }b$

If desired, this can be further simplified into

$log_{4 }3 + log_{2^{2} }2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} log_{2}2 + log_{4 }a + log_{4 }b$

$log_{4 }3 + \frac{1}{2} (1)+ log_{4 }a + log_{4 }b$

$\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Hence, the logarithm written as a sum of logarithm and simplified as much as possible is $\frac{1}{2} +log_{4 }3 + log_{4 }a + log_{4 }b$

Learn more on Simplifying logarithms here: brainly.com/question/17851187

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2 years ago

Y= 2.5x+ 5.8 when x = 0.6 pls find the function

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