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Elis [28]
3 years ago
6

An open box with a square base is to have a volume of 18 ft3. (a) find a function that models the surface area a of the box in t

erms of the length of one side of the base x.
Mathematics
1 answer:
stiks02 [169]3 years ago
5 0
2.7144 ft
hope i helped. your welcome. peace
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Answer:

The only options which are having same solution as the given equation is A, B and D.

Explanation:

Given the equation: \frac{3}{5}x+ \frac{2}{3} +x =\frac{1}{2}- \frac{1}{5}x ......[1]

Like terms are terms whose variables are the same.

In the given equation [1],

Combine like terms of variable x on LHS; we have

\frac{3x+5x}{5}+ \frac{2}{3} =\frac{1}{2}- \frac{1}{5}x

Simplify:

\frac{8x}{5}+\frac{2}{3} =\frac{1}{2}- \frac{1}{5}x

or we can write this as;

\frac{8}{5}x +\frac{2}{3} =\frac{1}{2}- \frac{1}{5}x .

LCM(Least Common Multiple) to change each fraction to make their denominators the same as the least common denominator.

Taking LCM to both sides of an equation [1] as;

LCM of 3, 5 on LHS is 15 and LCM of 2 , 5 on RHS is 10;

\frac{9x+10+15x}{15} = \frac{5-2x}{10}

By cross multiplication we get;

10 \cdot (9x+10+15x) = 15 \cdot (5-2x)

Divide both side by 5 we get;

2 \cdot (9x+10+15x) = 3 \cdot (5-2x)

Using distributive property on both sides of an equation (i.e,   a\cdot (b+c) =a\cdot b+a\cdot c )

we have;

18x+20+30x = 15-6x                 ......[2]

Additive Property of Equality states that allows one to add the same quantity to both sides of an equation.

Using additive property of equality:

Add 6x to both sides of an equation in [2];

18x+20+30x+6x = 15-6x+6x  

Simplify;

18x+20+30x+6x = 15  

Combine 18x and 6x  we get;

24x+20+30x= 15                      ......[3]

Subtraction Property of Equality states that allows one to subtract the same quantity to both sides of an equation.

Subtract 20 from both sides of an equation in [3] we get;

24x+20+30x-20= 15-20

Simplify:

24x+30x= -5

Therefore, from the given options only A, B and D have the same solution as \frac{3}{5}x+ \frac{2}{3} +x =\frac{1}{2}- \frac{1}{5}x








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we conclude that when we evaluate in x = 7, the given expression is equal to 12.

<h3></h3><h3>How to evaluate the expression?</h3>

Here we have the expression:

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Which represents the product of 6 and the sum between x and negative 5.

We want to evaluate it in x = 7, that means just replacing the variable in the given expression by the number 7, and then solving the expression.

Let's do that:

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In this way, we conclude that when we evaluate in x = 7, the given expression is equal to 12.

If you want to learn more about evaluating:

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