The answer would be a Tell Me if it’s wrong and I’ll solve it The best I can have nice day
Answer:
ℝ - {(-2/3),(3/2)}
Step-by-step explanation:
We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).
- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

- Domain of f(g(x)): We'll find its expression:

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

Lastly, we may write the domanin of f(g(x)):
![D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[](https://tex.z-dn.net/?f=D%28f%28g%28x%29%29%20%3D%20%5Cleft%5D-%5Cinfty%2C-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5B%5Ccup%5Cleft%5D-%5Cdfrac%7B2%7D%7B3%7D%2C%5Cdfrac%7B3%7D%7B2%7D%5Cright%5B%5Ccup%5Cleft%5D%5Cdfrac%7B3%7D%7B2%7D%2C%5Cinfty%5Cright%5B)
or, just writing in a shorter way:

Because this is an isosceles triangle, 3x = x + 10. Thus, 2x + 10 and x = 5.
With x=5, MN has the length 5+10, or 15.
Let the side length of the original square be x, then
1/4 x^2 = (x - 3)^2
x^2 = 4(x^2 - 6x + 9) = 4x^2 - 24x + 36
3x^2 - 24x + 36 = 0
3(x^2 - 8x + 12) = 0
x^2 - 8x + 12 = 0
x^2 - 2x - 6x + 12 = 0
x(x - 2) - 6(x - 2) = 0
(x - 6)(x - 2) = 0
x - 6 = 0 or x - 2 = 0
x = 6 or x = 2
but x cannot be 2 since the side length of the smaller square will be negative.
Therefore, the side length of the original square is 6 inches.