Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:
Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:
Using the additive rule of probability, we have the following equation for our problem:
the probability that the red die shows a six or the green die shows a six is 11/36.
1/12c = 0.6
To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).
12(1/12c) = 0.6*12
The 12 cancels out leaving this:
c = 0.6 * 12
c = 7.2
If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this:
6/10 simplifying it becomes, 3/5
3/5 * 12 = 36/5
Now! That was assuming 1/12c was written like this:
(1/12)c = 0.6
If it was actually written like this:
1/(12c) = 0.6 then you'll do this.
Multiply 0.6 by 12c. Which will get you 7.2c. After that you need to get c alone, so you divide both sides by 7.2. Yielding the result:
1/7.2 = c
c = 0.1389...
The answer is 5 I just took the test
You were supposed to find the area of the darkened area
Answer:
-3
Step-by-step explanation:
-15 divided by 5= -3
X=1,y=1
1 )4x+2y=6
2 ) x -y=3
2(x2) ) 2x - 2y=6
