Answer:
False
Step-by-step explanation:
As integer is a whole number that is not a fractional number that can be positive, negative, or zero.
Answer:
5 pounds of miniature chocolate and 2 butterscotch hard candies
Step-by-step explanation:
5 x $1.80 =$9 for 5 pounds of candy
2 x $1.00 =$2 for 2 pounds of candy
2 + 5 =7 pounds
7 pounds of candy using $11.00
Unit form is the other term for unit fraction, in which the number is written as a fraction/ ratio: <span>the top number is referred to as the numerator and the bottom number is referred to as the denominator.
In our case </span> the number is 5 hundreds x 10.
5 hundreds = 500
so, we have 500 x 10.
we have 10 wholes form 500.
10*500=5000
The simplest way to write number as a fraction is to multiply it with 1 but written as 10/10 for example:
5000*10/10=50000/10
Answer:
number Of Prizes % number Of Participants == 0
When we talk about division, a number 'A' is divisible by any other number 'B',
it means the remainder after division must be 0. And, we denote division for getting the remainder by '%' sign.
So, As per the question, we have to check whether numberOfPrizes is divisible by numberOfParticipants, the expression is
number Of Prizes % number Of Participants == 0
If number Of Prizes % number Of Participants == 0, condition satisfies, the answer will be True otherwise False
![a + 8 = - \dfrac 5 a](https://tex.z-dn.net/?f=a%20%2B%208%20%3D%20%20-%20%5Cdfrac%205%20a%20)
If I was solving this, which I suppose I am, my first step would be the clear the fractions by multiplying both sides by <em>a</em>.
![a^2 + 8a = - 5](https://tex.z-dn.net/?f=a%5E2%20%2B%208a%20%3D%20%20-%205)
That's there, first choice, SELECT IT
Then I'd bring the 5 to the other side;
![a^2 + 8a + 5 = 0](https://tex.z-dn.net/?f=a%5E2%20%2B%208a%20%2B%205%20%3D%200)
Not among the choices.
Then I'd attempt to factor, looking for a pair that multiplies to 5 and adds to 8; no joy there.
Shakespeare Quadratic Formula (2b or -2b) trick: ![x^2 - 2bx + c \textrm{ has zeros at } x=b\pm \sqrt{b^2-c}](https://tex.z-dn.net/?f=x%5E2%20-%202bx%20%2B%20c%20%5Ctextrm%7B%20has%20zeros%20at%20%7D%20x%3Db%5Cpm%20%5Csqrt%7Bb%5E2-c%7D)
![a = 4 \pm \sqrt{4^2-5} = 4\pm \sqrt{11}](https://tex.z-dn.net/?f=a%20%3D%204%20%5Cpm%20%5Csqrt%7B4%5E2-5%7D%20%3D%204%5Cpm%20%5Csqrt%7B11%7D)
All the other choices have nice rational answers so can't be right.
First choice only