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Marat540 [252]
3 years ago
7

The population of a town was 57,000 in 1980 and 81,000 in 2010. Assume the rate of population increase is constant. What will th

e population be in 2015?
Mathematics
1 answer:
sergejj [24]3 years ago
5 0
You have to find the equation that would fit the situation which would be 57,000+800x= population. Then the difference in the years from the year you are trying to figure out to 1980 is plugged in for x. so you would do 2015-1980=35 you would then plug in 35 of x in the equation. 57,000+800(35)=85,000. 
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Answer:

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Find the theoretical probability for rolling 6 as well as the probability for a 1
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Read 2 more answers
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Vesnalui [34]

Answer:

(a) X\sim N(\mu = 73, \sigma = 16)

(b) 0.7910

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Step-by-step explanation:

Let <em>X</em> = amount of time that people spend at Grover Hot Springs.

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(a)

The distribution of the random variable <em>X</em> is:

X\sim N(\mu = 73, \sigma = 16)

(b)

Compute the probability that a randomly selected person at the hot springs stays longer than 60 minutes as follows:

P(X>60)=P(\frac{X-\mu}{\sigma}>\frac{60-73}{16})\\=P(Z>-0.8125)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays longer than an hour is 0.7910.

(c)

Compute the probability that a randomly selected person at the hot springs stays less than 45 minutes as follows:

P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly selected person at the hot springs stays less than 45 minutes is 0.0401.

(d)

Compute the probability that a randomly person spends between 60 and 90 minutes at the hot springs as follows:

P(60

*Use a <em>z</em>-table for the probability.

Thus, the probability that a randomly person spends between 60 and 90 minutes at the hot springs is 0.6464

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babunello [35]

Answer:

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Taking LCM

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6 0
3 years ago
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