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4 years ago

11

Kevin is an expert pastry chef. He can bake and decorate an entire cake in 30 minutes. He can also bake and frost a cupcake in 1

0 minutes. If he works for 12 hours on these two tasks and ends up making a total of 3 cakes, how many cupcakes did he make?

2 answers:

Llana [10]4 years ago

7 0

63 cupcakes is the amount he made.

andriy [413]4 years ago

5 0

Answer:

63 cupcakes

Step-by-step explanation:

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Please help me with this one!!

Tema [17]

Answer:

$21 in^{2}$

Step-by-step explanation:

The square in the middle has a length and width of 3, so multiply. <u>9</u>.

All of the triangles have a base of 3 and a height of 2. The area equation for triangles is

$A=bh\frac{1}{2}$

So base*height is 6. Divide that by 2 or multiply by 1/2.

You get 3. There are 4 triangles, so multiply <em>that</em> by 4. <u>12</u>.

Add 12 and 9 together, and you get:

$21 in^{2}$

I hope this helps!

6 0

3 years ago

PLS I REALLY NEED HELP?

ss7ja [257]

Well you have to subtract. i think you have to do 15-10% which is 14.9

8 0

3 years ago

Add three data values to the following data set so the mean increases by 10 and the median does not change. {42, 37, 32, 29, 20}

aksik [14]

Sum of the numbers in the set: 42+37+32+29+20 =160

Current mean: 160/5 = 32

Median = the valvue of the middle = 32.

New mean: 32+10= 42.

Sum of numbers in the new set = 42*8 = 336

Difference: 336 - 160 = 176

I want to include 32, so that the new median stays in 32.

So the other two numbers must add 176 - 32 = 144

I will use a smaller number than 32 and the other greater (again in order to keep the same median.

I will choose 28 and 144 - 28 = 116.

So my three new numbers are 28, 32 and 116 and the new set is {116, 42, 37, 32, 32, 29,28, 20}

Checking:

Sum of the terms: 116+42+37+32+32+29+28+20 = 336

Mean = 336 / 8 = 42, which is 10 more than the original mean.

And the new median is (32+32)/2 = 32. The same of the original set.

8 0

3 years ago

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f

Ganezh [65]

Answer:

299.99 miles

Step-by-step explanation:

Since the plane traveled due west,

The total angle is 49.17 + 90

Represent that with θ

θ = 49.17 + 90

θ = 139.17.

Represent the sides as

A = 170

B = 150

C = unknown

Since, θ is opposite side C, side C can be calculated using cosine formula as;

C² = A² + B² - 2ABCosθ

Substitute values for A, B and θ

C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17

C² = 22500 + 28900 - 51000 * Cos 139.17

C² = 51400 - 51000 (−0.7567)

C² = 51400 + 38,591.7

C² = 89,991.7

Take Square Root of both sides

C = 299.9861663477167

C = 299.99 miles (Approximated)

Hence, the distance between the plane and the airport is 299.99 miles

8 0

4 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is

Leto [7]

Answer:

$t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827$

The degrees of freedom are given by:

$df=n-1=23-1=22$

And the p value taking in count that we have a bilateral test we got:

$p_v =2*P(t_{(22)}>0.827)=0.417$

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

Step-by-step explanation:

Information given

$\bar X=435$ represent the mean for the weight

$s=\sqrt{841}=29$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =430$ represent the value that we want to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We are trying to proof if the filling machine works correctly at the 430 gram setting, so then the system of hypothesis for this case are:

Null hypothesis: $\mu = 430$

Alternative hypothesis: $\mu \neq 430$

In order to cehck the hypothesis the statistic for a one sample mean test is given by

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we have this:

$t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827$

The degrees of freedom are given by:

$df=n-1=23-1=22$

And the p value taking in count that we have a bilateral test we got:

$p_v =2*P(t_{(22)}>0.827)=0.417$

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

8 0

3 years ago