Question

A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coach bought 6 more hamburgers and 2 more fries for $16.60. Find the cost of each.

Answer 1

Basically this is a systems of equations question. We set up two equations, X is hamburgers Y is fries

8x + 5y = 24
6x + 2y = 16.60
 
then you solve for each to get your answer.

Answer 2

Answer : The cost of hamburgers and fries is, $2.5 and $0.8

Step-by-step explanation :

Let the cost of hamburgers be, x and the cost of fries be, y.

Thus the two equation will be:

$8x+5y=24$     ...........(1)

$6x+2y=16.60$    .............(2)

Using substitution method:

From equation 1 we have to determine the value of 'y'.

$8x+5y=24$

$5y=24-8x$

$y=\frac{24-8x}{5}$        ........(3)

Now put equation 3 in 2, we get:

$6x+2y=16.60$

$6x+2\times (\frac{24-8x}{5})=16.60$

$6x+(\frac{48-16x}{5})=16.60$

$\frac{30x+48-16x}{5}=16.60$

$30x+48-16x=83$

$14x=35$

$x=2.5$

Now put the value of x in equation 3, we get:

$y=\frac{24-8x}{5}$

$y=\frac{24-8\times 2.5}{5}$

$y=\frac{24-20}{5}$

$y=\frac{4}{5}$

$y=0.8$

Thus, the cost of hamburgers and fries is, $2.5 and $0.8