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3 years ago

8

4 cards are chosen at random from a deck of 52 cards without replacement. what's the probability of choosing a ten, a nine, an e

ight, and a seven in order?

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

Answer:

12%

Step-by-step explanation:

im not sure so sorry if wrong

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Need to simplify (x^2y)^4

svlad2 [7]

Answer:

$x^{8y}$

Step-by-step explanation:

$(x^{2y})^4 = x^{4*(2y)} = x^{8y}$

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3 years ago

3=x+9<br> PLEASE SHOW WORK. SOLVE AND CHECK.

Vika [28.1K]

Answer:

x = —6

Step-by-step explanation:

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Collect like terms

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3 years ago

jamal is going to borrow $14,000 from his credit union to buy a used car. The APR is 7.0% and the length of the loan is 4 years.

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3 years ago

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The value of the given digits the 4s in 244

Digiron [165]

244

The 4's are in the ONE's and TEN's places

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3 years ago

If you are solving y 2+2y=48 by completing the square, the next line would be

snow_tiger [21]

For this case we have the following equation:

$y ^ 2 + 2y = 48$

By completing squares we have:

Step 1:

Add $(\frac {b} {2}) ^ 2$ on both sides:

$y ^ 2 + 2y + 1 = 48 + 1$

Step 2:

We rewrite the equation:

$(y + 1) ^ 2 = 49$

Step 3:

We solve the equation:

$y = \pm \sqrt {49} -1\\y = \pm7-1$

Solutions:

$y = 6\\y = -8$

Answer:

the next line would be:

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3 years ago

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