X=y+z
subtract y from both sides
-y+x=z that is your answer
Answer:
Step-by-step explanation:
- <em>Options are:
</em>
- <em>A. 25c
</em>
- <em>B. 0.75c
</em>
- <em>C. 1.25c
</em>
- <em>D. 1.25c - 1.25
</em>
---------------------
Original price = c
Markup = 25%
<u>Markup price is:</u>
- c + 25% =
- c + 0.25c =
- 1.25c
Correct option is C
This is tricky
lets try substituting y = √)6x - 9)
√(6 - y) + √(6x + y) = √6
squaring both sides:-
6 - y + 6 + y - 2√(6 - y)(6 + y) = 6
12 - 2√(6 - y)(6 + y) = 6
√(6 - y)(6 + y) = (6-12) / -2 = 3
Squaring both sides:-
(6 - y)(6 + y) = 9
36 - y^2 = 9
y^2 = 27
y = +/-√27
√(6x - 9) = +/- 27
6x - 9 = 729
x = 738/6 = 123
This cannot be a solution because we would have a negative value for the
second square root
I would say that no solution exist.
As far as I know 0 IS a rational number. The only ones that are not rational are negative numbers. :) Though I could be wrong.....
Hello from MrBillDoesMath!
Answer: 1, 4, 9. 16, 25, 36
Discussion:
If by "square array" you mean an array of perfect squares, the answer is
1, 4, 9. 16, 25, 36
Thank you,
MrB
