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Karolina [17]
2 years ago
12

Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always

true, sometimes true, or never true. Provide evidence to support your conclusion.
Mathematics
2 answers:
DIA [1.3K]2 years ago
8 0

Answer:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

Liono4ka [1.6K]2 years ago
7 0

Answer:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

Step-by-step explanation:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

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In a group of 60 workers they get paid an average of 80$ a day per person.
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48 workers earn $75 a day.

Step-by-step explanation:

Let x people earn 75 a day then 60-x earn 100 dollars a day.

Average is $80 a day so total paid out to the 60 workers

= 60*80 = $4800.

So  75x + 100(60-x) = 4800

75x + 6000 - 100x = 4800

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1 year ago
Abbie spent 5/8 of her money and saved the rest. If she spent $45. how much money did she have at first?
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Monique picked 32 quarters of beans how many pecks did she pick
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3 years ago
The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca
Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So \mu = 186.94, \mu = 0.372, X = 185.85

Z = \frac{X - \mu}{\sigma}

Z = \frac{185.85 - 186.94}{0.372}

Z = -2.93

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So \mu = 110.7, \sigma = 0.115, X = 110.48

Z = \frac{X - \mu}{\sigma}

Z = \frac{110.48 - 110.7}{0.115}

Z = -1.91

Karen finishing time was 1.91 standard deviations below the mean.

Karen had a finish time with a z-score -1.91.

Who had the more convincing victory?

Sam finishing time was 2.93 standard deviations below the mean.

Karen finishing time was 1.91 standard deviations below the mean.

Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.

So Sam had the more convincing victory.

8 0
3 years ago
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