Answer:
45-40
Step-by-step explanation:
The first interval is 15-19.
The width of this interval is: 19-15=4
The second interval is 30-34.
The width of this interval is: 34-30=4
The third interval is 40-45.
The width of this interval is: 45-40=5
The fourth interval is 45-49.
The width of this interval is: 49-45=4
<h3>Therefore the interval that is not equal to the other three is 45-40</h3>
A is the answer. Reflection and rotation.
The answer is J. 1/(x^2-x)
A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Answer:
B
Step-by-step explanation:
Use the formula for radius and circle circumference.

Since we know the diameter, if we divide that by 2, we can get the radius.

Now we can plug that value into the circumference formula to get the circumference.

*Since we're rounding to the nearest inch.