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dalvyx [7]
3 years ago
14

Upon descent, an airplane is 20,000 feet above the ground. The air traffic control tower is 200 feet tall. It is determined that

the angle of elevation from the top of the tower to the plane is 15°. To the nearest mile, find the ground distance from the airplane to the tower.​
Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

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11kx+13kx=6 for x please and thank u
bogdanovich [222]
24kx = 6
kx=6/24
kx=1/4
x=1/4/k
x = 1/4k

Answer: D) or the fourth option.
8 0
3 years ago
The sum of a number and its square is 42. Which equation can be used to find the two numbers for which this is true?
Karolina [17]

Answer:

x^2 + x = 42

Step-by-step explanation:

Let x = the number

Is means equals and sum means add

The sum of a number and its square is 42

x + x^2 = 42

5 0
3 years ago
Read 2 more answers
Jon's coin collection consists of quarters, dimes and nickels. If the ratio of quarters to dimes is 5:2, and the ratio of dimes
Margarita [4]

Answer:

The ratio of quarters to nickels is:

  • <u>15:8</u>

Step-by-step explanation:

To solve the exercise, you must first consider how big is the ratio of each one to the other, when it is mentioned that the ratio of quarters to dimes is 5:2 it means that for every 5 quarters, Jon has 2 dimes, for the more quarters there are with respect to the dimes, we simply divide the larger value by the smaller:

  • 5/2 = 2.5

Thus, we know that there are 2.5 more quarters than dimes. Now the following proportion: the ratio of dimes to nickels is 3:4, which means that for every 3 dimes there are 4 nickels, as the nickels are greater in quantity, we are going to see how many times they are greater in proportion than the dimes making again a division of the major over the minor:

  • 4/3 = 1.33333333333 (<em>we are going to use the fractional number so as not to lose decimals</em>).

As we can see, the nickels are a little more than 1 with respect to the dimes, now we are going to create two formulas with those values:

  • <em>q = 2.5d </em>
  • <em>n = 4/3 d</em>

Where:

  • q = quarters
  • d = dimes
  • n = nickels

As you see. We only express the calculated proportions, at first glance you can identify that the number of quarters is greater, but to know how much greater with respect to nickels we are going to divide the two values ​​that accompany "d" in the formulas:

  • <u>2.5 / (4/3) = 15/8</u>

If we express it in ratio as it is in the exercise, we obtain:

  • <u>15:8</u>

So, <u>15:8 is the ratio of quarters to nickels</u>, <em>which means that for every 15 quarters, jon has 8 nickels.</em>

8 0
3 years ago
Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
Jackson rides his bike from his home for 30 minutes at a fast pace. He stops to rest for 20 minutes, and then continues riding i
Dimas [21]

Answer:

For the first 30 minutes, we will have a line with a given steepness, this will represent the 30 minutes riding at a fast pace.

Then he stops for 20 minutes, we will represent this with a constant line.

Then he again moves for another 30 minutes, but with a slower pace than in the first 30 minutes, then this line will be less steep than the first line.

A sketch of this situation can be seen below.

5 0
3 years ago
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