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OlgaM077 [116]
3 years ago
13

I just need help in this last question plsssss

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

B) 0.8

Step-by-step explanation:

If events are said to be independent, then just multiply the probability of the first event by the second if they are supposed to be happening together.

P (A) * P (B) = 0.8 x 1 = 0.8

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A 2-column table with 5 rows. The first column is labeled x with entries negative 3, negative 2, 0, 2, 3. The second column is l
pashok25 [27]

Answer

-15

3

Just took the test on edge.

6 0
3 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
Whats is 67.24 as a mixed number
masha68 [24]
<span>67 24 out of 100 i believe</span>
6 0
3 years ago
Read 2 more answers
Braceleftzf y = 8/7 x − 2/3 <br> 8/3 x + y = 5/9
givi [52]

Answer:

  (x, y) = (77/240, -3/10)

Step-by-step explanation:

It is convenient to write the equations in standard form.

Multiplying the first equation by 21 gives ...

  21y = 24x -14

Multiplying the second equation by 8 gives ...

  24x +9y = 5

Then the system of equations in standard form is ...

  • 24x -21y = 14
  • 24x +9y = 5

Subtracting the first from the second, we get ...

  (24x +9y) -(24x -21y) = (5) -(14)

  30y = -9

  y = -9/30 = -3/10

Substituting this into the second equation, we have ...

  24x +9(-3/10) = 5

  24x = 7.7 . . . . . . . add 27/10

  x = 7.7/24 = 77/240

The solution is (x, y) = (77/240, -3/10).

7 0
2 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
2 years ago
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