Answer:
No solutions. You can’t have a negative absolute value.
It's hard to help if you can't provide everything with the question
Answer:
The probability that 75% or more of the women in the sample have been on a diet is 0.037.
Step-by-step explanation:
Let <em>X</em> = number of college women on a diet.
The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.
The sample of women selected is, <em>n</em> = 267.
The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.
As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (
) follows a Normal distribution.
The mean of this distribution is:

The standard deviation of this distribution is: 
Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

**Use the <em>z</em>-table for the probability.

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.
Answer:
C. 15
Step-by-step explanation:
-4/3x-6=-26
The first step is to add 6 to each side
-4/3x-6+6=-26+6
-4/3x =-20
Now multiply by -3/4 to isolate x.
-3/4 * -4/3x = -3/4 * -20
x = 60/4
x = 15
Answer:
Step-by-step explanation:
2x⁴ + 4x³ - 30x² = 2x²*(x² + 2x - 15)
x² + 2x - 15
Sum = 2
Product = -15
Factors = 5 ; (-3)
x² + 2x - 15 = x² + 5x - 3x - 3 *5
= x(x + 5) - 3(x + 5)
= (x + 5)(x - 3)
2x⁴ + 4x³ - 30x² = (2x²) (x + 5)(x - 3)