Given:
Reflect square JKLM with J(1, 4), K(6, 5), L(7, 0) and M(2, -1) in the y-axis.
To find:
The coordinates of M'.
Solution:
We have, M(2, -1) .
If a figure reflected over the y-axis then
Using this rule, we get
Therefore, the coordinates of point M' are (-2,-1).
domain- (-3,-1, 1, 2, 3)
Range- (2,0,0,-2,3)
Answer:
2
Step-by-step explanation:
Let f(x) = 2x – 1
Substitute (x + b) in place of x.
f(x + b) = 2(x + b) – 1
= 2x + 2x –1
To find :
(Cancel common term)
Hence,