Four (4) fair dice are rolled. what is the probability that the total is 21
1 answer:
Short Answer 5/216Comment The question really is, how many different types of throws with 4 dice will give 21? You can count them Pattern 1 6663 Pattern 2 5556 Pattern 3 [ The hard one] 6654 Patterns 1 and 2 give 4 each. 6 6 6 3 6 6 3 6 6 3 6 6 3 6 6 6 5553 will do the same thing Both can be found by (4/1) as a combination. Now for 6654 That gives 12 6 6 5 4 6 6 4 5 6 5 4 6 6 5 6 4 6 4 5 6 6 4 6 5 5 6 4 6 5 6 6 4 5 4 6 6 4 5 6 6 4 6 5 6 4 6 6 5 That should total 12 The total number of ways of getting 21 with this pattern is 12Total successes 12 + 4 + 4 = 30What is the total number of ways you can throw 4 dice? Total = 6 * 6 * 6 * 6 = 1296What is the probability of success? 30 / 1296 = 5 / 216
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