What does the rate of change mean in terms of the ball's movement?

The area of the circle is 64pie cm. What is the radius in cm?

Vinil7 [7]

Answer: 8 centimeters

Step-by-step explanation: To find the radius of the circle, remember that the formula for the area of a circle is πr² and since we're given that the area of our circle is 64π, we can set up the equation 64π = πr².

To solve for <em>r</em>, we first divide both sides of the equation by π.

On the left side, the π's cancel and we're left with 64 and on the right side, the π's cancel and we're left with r².

So we have 64 = r².

Next, we take the square root of both sides to get 8 = r.

So the radius of our circle is 8 centimeters.

8 0

3 years ago

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In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

3 years ago

How do you do the area and how to do it to the nearest tenth

lord [1]

You just put I line in the middle and you times high times base the do the other one then add your answers up that should be your finely answer

6 0

3 years ago

Statistics Question. Use the Desmos graphing calculator to find the least-squares regression line for the dataset in the table:

Soloha48 [4]

Given:

The table of values.

To find:

The least-squares regression line for the data set in the table by using the desmos graphing calculator.

Solution:

The general form of least-squares regression line is:

$\hat{y}=mx+b$ ...(i)

Where, m is the slope and b is the y-intercept.

By using the desmos graphing calculator, we get

$m\approx 2.55,b\approx -6.435$

Substitute these values in (i).

$\hat{y}=(2.55)x+(-6.435)$

$\hat{y}=2.55x-6.435$

Therefore, the correct option is A.

8 0

3 years ago

Cada pregunta y complete con V si considera que la aseveración es verdadera y una F si considera que es falsa (15 puntos total)(

Natali [406]

Answer:

sey

Step-by-step explanation:

5 0

3 years ago

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What does the rate of change mean in terms of the ball's movement?​

What does the rate of change mean in terms of the ball's movement?