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denis-greek [22]
3 years ago
11

Which of the following expressions could NOT be used to find the volume of the sheet cake? Select all that apply.

Mathematics
1 answer:
andre [41]3 years ago
7 0

Incorrect

60 × 3

Correct

12 + 5 + 3

Incorrect

3 × 5 × 12

Correct

12 × 5

Correct

(12 × 5) + 3

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Paula weeded 40% of her garden in 8 minutes. How many minutes will it take her to weed all of her garden?
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Part=percent*whole

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Which is the smallest number in this set of numbers? <br> A. √8<br> B. 14/5<br> C. 2.28<br> D. 2.288
-Dominant- [34]

Answer:

B.

Step-by-step explanation:

a = 2.828

b = 2.800

c = 2.288

d = 2.288

8 0
3 years ago
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Hello,
balu736 [363]

Answer:

yesss it makes sense!!!!!!!!!!!

6 0
2 years ago
g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur
sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

\displaystyle V = \pi r^2h

Substitute:

\displaystyle (300) = \pi r^2 h

Solve for <em>h: </em>

\displaystyle \frac{300}{\pi r^2} = h

Recall that the surface area of a cylinder is given by:

\displaystyle A = 2\pi r^2 + 2\pi rh

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r}  \end{aligned}

Find its derivative:

\displaystyle A' = 4\pi r - \frac{600}{r^2}

Solve for its zero(s):

\displaystyle \begin{aligned} (0) &= 4\pi r  - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

\displaystyle  \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2}  \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm}   \end{aligned}

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0
3 years ago
Charlotte is working two summer jobs, making $7 per hour washing cars and making $15 per hour clearing tables. In a given week,
FrozenT [24]

Answer:

Claire must work 4 hours cleaning tables and 5 hours washing cars to earn more than $ 90.

Since Claire is working two summer jobs, making $ 7 per hour washing cars and making $ 15 per hour clearing tables, and in a given week, she can work at most 9 total hours and must earn a minimum of $ 90, to determine one possible solution the following calculation must be performed:

15 x 9 = 135

135 - 90 = 45

45/7 = 6.42

6 x 7 + 3 x 15 = 42 + 45 = 87

5 x 7 + 4 x 15 = 35 + 60 = 95

Therefore, at a minimum, Claire must work 4 hours cleaning tables and 5 hours washing cars to earn more than $ 90.

3 0
1 year ago
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