All categories

3 years ago

Each side on a sticky note measures 9 centimeters. what is the srea of the sticky note?

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

All sides are equal. So sticky note is in the shape of square.

Area = side * side = 9 * 9 = 81 sq.cm

You might be interested in

Expand the expression and combine like terms:<br> 20(−1.5r+0.75)

PtichkaEL [24]

20( -1.5r + 0.75)
Multiply everything by 20

= -30r + 15

4 0

3 years ago

Read 2 more answers

Sarah worked 8 more hours than Paida (algebraic expression) ___

seropon [69]

X+8
2x
x-3
8 more hours
twice the number
3 years younger

8 0

3 years ago

Priscilla can make 4 bracelets in 17 minutes. At this rate, how many bracelets can she make in 34 minutes?

andrew11 [14]

4 bracelets/17 minutes = x bracelets/34 minutes
cross multiply: 4 · 34 = 17 · x
Divide both sides by 17: (4 · 34)/17 = x
x = 8

Answer: 8 bracelets

6 0

3 years ago

Find the solutions of the equation.

FromTheMoon [43]

Answer:

it is gonna be

Step-by-step explanation:

1902837456734832902398457675483920129384576574839202398475

sorry i dont know i need more points

8 0

3 years ago

A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15

Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: $Perimeter=2(Length+Width)\\$

Now, Putting values in formula for finding Width w:

$Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8$

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

6 0

3 years ago