Ok so you have 4, x^6 / 2, x^4. Now divide the coefficient so 4/2=2. So 2 x^6/x^4, now subtract the numerator by the denominator so x^6-x^4=x^2 so now you have 2x^2

Answer: 2x^2

5 0

3 years ago

Solve the equation (1 + x²)dy +xydx= 0

Tatiana [17]

Answer:

$y=\frac{c}{\sqrt[]{x^2+1} }$

Step-by-step explanation:

(1 + x²)dy +xydx= 0

$(1+x^2)dy=-xydx\\\frac{1}{y}dy=\frac{-x}{x^2+1}dx\\$

Integrate both side

$lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }$

7 0

3 years ago

In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and segment DF is congruent to segment BD . Point C is the point of intersection betw

Rzqust [24]

Answer:

Step-by-step explanation:

Given:

∠DCE ≅ ∠DEC

∠B ≅ ∠F

DF ≅ BD

To prove:

ΔABC ≅ ΔGFE

Solution:

Statements Reasons

1). ∠DCE ≅ ∠DEC 1). Given

2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the

congruent angles.

3). ∠B ≅ ∠F 3). Given

4). DB ≅ DF 4). Given

5). DC + CB ≅ DE + EF 5). Segment addition postulate

6). DC ≅ DE 6). Property of isosceles triangle

7). CB ≅ EF 7). Transitive property

8). ΔABC ≅ ΔGFE 8). ASA property of congruence

4 0

3 years ago