Answer: 6
Step-by-step explanation:
if 10 out of the 20 liked r&j the most. half of those 20 liked it the most, so, based on that, the out of the next group of students (12 here) half of them you should expect to answer with r&j being there favorite
The average rate of change of f(x) on the interval [5, 5 + h] is 1
<h3>How to find the
average rate of change of f(x) on the interval [5, 5 + h]?</h3>
The equation of the function is given as:
f(x) = x + 11
The interval is given as: [5, 5 + h]
So, we start by calculating f(5) and f(5 + h)
This gives
f(5) = 5 + 11 = 16
f(5 + h) = 5 + h + 11 = h + 16
The average rate of change of f(x) on the interval [5, 5 + h] is then calculated as:
Rate = [f(5 + h) - f(5)]/[5 + h - 5]
Substitute the known values in the above equation
Rate = (h + 16 - 16)/(5 + h - 5)
Evaluate the sum and the difference
Rate = h/h
This gives
Rate = 1
Hence, the average rate of change of f(x) on the interval [5, 5 + h] is 1
Read more about the average rate of change at
brainly.com/question/8728504
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Answer:
I think is 12x2 +48x-27 but I'm confused
64x^2+8xy/4xy^2. This should be what you’re looking for hopefully
(0,0) is a point that also lays on the graph
