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3 years ago

Find the mean. Round to the nearest tenth if necessary.

Mathematics

2 answers:

myrzilka [38]3 years ago

6 0

Answer:

27 is the answer

Step-by-step explanation:

Took the test and got it right

kondor19780726 [428]3 years ago

5 0

Answer:

Step-by-step explanation:

The actual mean is 27.008333333333, round that as you will.

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Mariana solved the equation below. Identify her ERROR and EXPLAIN what she did wrong. -3(2x-4)=-12 -6x-12=-12 -6x=0 x=0

nydimaria [60]

Answer:

Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead

Step-by-step explanation:

Mariana workings:

-3(2x - 4) = -12

-6x - 12 = -12

Her error was multiplying -3 and -4 which gives +12 but she wrote -12 instead

-6x = 0

x=0

Correct workings:

-3(2x - 4) = -12

-6x + 12 = - 12

-6x = -12 - 12

-6x = -24

x = -24/-6

x = 4

8 0

3 years ago

Which expression is equivalent to 1.5x + 12 + 4x?

cestrela7 [59]

An equation that is equivalent to that equation is 5.5x + 12.

8 0

3 years ago

Read 2 more answers

Please help me solve please

Marat540 [252]

The picture isn’t included in this

3 0

3 years ago

PLS HELP!

wolverine [178]

Given:

Alexis has a rectangular backyard that is 50 yards by 55 yards.

She wants to build a fence that stretches diagonally from one corner to the opposite corner.

To find:

The length of the fencing she needs.

Solution:

We have,

Length = 50 yards

Width = 55 yards

We know that, the diagonal of a rectangle is

$Diagonal=\sqrt{length^2+width^2}$

$Diagonal=\sqrt{(50)^2+(55)^2}$

$Diagonal=\sqrt{2500+3025}$

$Diagonal=\sqrt{5525
}$

On further simplification, we get

$Diagonal=74.3303437$

$Diagonal\approx 74.3$

Therefore, the length of the required fencing is 74.3 yards.

8 0

3 years ago

If the length of a rectangle is 8 cm, and the diagonal is 17 cm. Find the length of the width.

viva [34]

$8 \sqrt{17}$

which is 2.125 cm

Answer:2.125 cm

4 0

4 years ago