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Nana76 [90]
3 years ago
12

William picked 3 3/8

Mathematics
1 answer:
zalisa [80]3 years ago
8 0
What is this asking I have no idea
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Find the amount in a continuously compounded account for the following condition. ​Principal, ​$​4000; Annual interest​ rate, 5.
soldi70 [24.7K]
<h3>Answer:  4745.96 dollars</h3>

=======================================================

Explanation:

We have this given info

  • P = 4000 = principal
  • r = 0.057 = annual interest rate in decimal form
  • t = 3 = number of years

Use this to plug into the formula below

A = Pe^{r*t}\\\\A = 4000*e^{0.057*3}\\\\A \approx 4,745.96299608713\\\\A \approx 4,745.96\\\\

You'll need your calculator, and the calculator needs the "e" button.

The "e" refers to the special constant 2.718... which is similar to pi = 3.14...

7 0
1 year ago
P^3•9^2 (P^4•9^n•R^3/R^4)= P^7 9^5 1^7<br><br> What is n?
kkurt [141]

Answer:

ssssssssssssssssssssssssssssssssssssssssss

Step-by-step explanation:

sssssssssss

8 0
2 years ago
Please help, will be greatful!
zvonat [6]

Answer:

y is 8

Step-by-step explanation:

First u do 13y-9y=4y

so you then have 4y-5=27

then you plus 5 to 27

u then have 4y=32

then divide 32 by 4

so you will get y=8

8 0
2 years ago
Read 2 more answers
Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
What is the sum of the geometric sequence 1,3,9... if there were 11 terms?
Delicious77 [7]

Answer:

88,573

Step-by-step explanation:

3 0
3 years ago
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