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Ne4ueva [31]
3 years ago
10

Anybody willing to help?

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

Answer:

16 is H.9

17. is A.9

Step-by-step explanation:

Hope it helped! ^_^

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This list shows the age at which 43 U.S. Presidents began their terms.
Artist 52 [7]

The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

The best way to decide the appropriate interval would be to find the range of the numbers.

We have given a data set,

<h3>What is the smallest value in the data?</h3>

The minimum is the smallest value in the data set. The maximum is the largest value in the data set.

<h3>What is the largest minus the smallest? </h3>

This would be 69-42=27.

If you need six intervals you would need to round 27 up to 30 to be able to divide it out evenly and include all of the data.

The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

This way you are one over and one under the highest and lowest values.

Therefore, The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

To learn more about the interval visit:

brainly.com/question/12221823

#SPJ1

4 0
2 years ago
What is the measure of angle k?
Murljashka [212]

9514 1404 393

Answer:

  59°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

  ∠N +∠L = 180°

  (a +16) +(a -18) = 180

  2a = 182 . . . . . . . . . . add 2

  a = 91 . . . . . . . . . . . . divide by 2

Then the measure of angle M is ...

  ∠M = (a+30)° = (91 +30)° = 121°

and angle K is its supplement.

  ∠K = 180° -121°

  ∠K = 59°

8 0
3 years ago
Tell whether the ordered pair (−1, 4) is a solution of the system.<br><br> -2x-3y=-10<br> -3x+y=7
LuckyWell [14K]

Answer:

-1

Step-by-step explanation:

5 0
3 years ago
Simplify. −5x4(−3x2+4x−2)
Serggg [28]
The answers my dear friends is 15x^6-20x^5+10x^4
3 0
3 years ago
Read 2 more answers
The most recent public health statistics available indicate that 23.6​% of American adults smoke cigarettes. Using the​ 68-95-99
artcher [175]

Answer:

There is a​ 68% chance that between 17​% and 30​% are​ smokers.

There is a​ 95% chance that between 10​% and 37​% are​ smokers.

There is a​ 99.7% chance that between 4​% and 44​% are​ smokers.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of the sampling distribution of sample proportion is:

 \mu_{\hat p}=p\\

The standard deviation of the sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Given:

<em>n</em> = 40

<em>p</em> = 0.236

Compute the mean and standard deviation of this sampling distribution of sample proportion as follows:

\mu_{\hat p}=p=0.236

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.236(1-0.236)}{40}}=0.067

The Empirical Rule states that in a normal distribution with mean <em>µ</em> and standard deviation <em>σ</em>, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be divided into three parts:

  • 68% data falls within 1 standard-deviation of the mean.  

        That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.

  • 95% data falls within 2 standard-deviations of the mean.

        That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.

  • 99.7% data falls within 3 standard-deviations of the mean.

        That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.

Compute the range of values that has a probability of 68% as follows:

P (\mu_{\hat p} - \sigma_{\hat p} \leq  \hat p \leq  \mu_{\hat p} + \sigma_{\hat p}) = 0.68\\P(0.236-0.067\leq  \hat p \leq 0.236+0.067)=0.68\\P(0.169\leq  \hat p \leq0.303)=0.68\\P(0.17\leq  \hat p \leq0.30)=0.68

Thus, there is a​ 68% chance that between 17​% and 30​% are​ smokers.

Compute the range of values that has a probability of 95% as follows:

P (\mu_{\hat p} - 2\sigma_{\hat p} \leq  \hat p \leq  \mu_{\hat p} + 2\sigma_{\hat p}) = 0.95\\P(0.236-2\times 0.067\leq  \hat p \leq 0.236+2\times0.067)=0.95\\P(0.102\leq  \hat p \leq 0.370)=0.95\\P(0.10\leq  \hat p \leq0.37)=0.95

Thus, there is a​ 95% chance that between 10​% and 37​% are​ smokers.

Compute the range of values that has a probability of 99.7% as follows:

P (\mu_{\hat p} - 3\sigma_{\hat p} \leq  \hat p \leq  \mu_{\hat p} + 3\sigma_{\hat p}) = 0.997\\P(0.236-3\times 0.067\leq  \hat p \leq 0.236+3\times0.067)=0.997\\P(0.035\leq  \hat p \leq 0.437)=0.997\\P(0.04\leq  \hat p \leq0.44)=0.997

Thus, there is a​ 99.7% chance that between 4​% and 44​% are​ smokers.

7 0
3 years ago
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