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lakkis [162]
3 years ago
13

IF UR GOOD AT CHEM PLZ ANSWER MY PREVIOUS QUESTIONS ON MY PROFILE, I NEED HELP!!

Chemistry
1 answer:
erastova [34]3 years ago
7 0

Answer:

Ok, I'll try

Explanation:

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What Are DNA-Binding Proteins?

DNA is the blueprint for the cell. It contains information that codes for all of our traits. Essentially, our DNA is what makes us, us. But, DNA doesn't do this in isolation. There are thousands of proteins in our cells that help modulate DNA's functions. These proteins are called DNA-binding proteins, because they attach to DNA.

DNA binding proteins do many jobs including controlling protein production, regulating cell growth and division, and storing DNA inside the nucleus. Thus, if DNA is the blueprint to build the human body, then DNA-binding proteins are the parts of the cell that read and interpret the instructions to actually create and maintain the body. Let's look at the different types of DNA-binding proteins and examples of each.

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Which of these is an example of biotic factor
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How many grams of al(oh)3 (molar mass = 78.0 g/mol) can be produced from the reaction of 48.6 ml of .15 m koh with excess al2(so
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Taking into account the reaction stoichiometry, 0.18954 grams of Al(OH)₃ are formed from the reaction of 48.6 mL (0.0486 L) of 0.15 M KOH with excess Al₂(SO₄)₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Al₂(SO₄)₃ + 6 KOH → 2 Al(OH)₃ + 3 K₂SO₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al₂(SO₄)₃: 1 mole
  • KOH: 6 moles
  • Al(OH)₃: 2 moles
  • K₂SO₄: 3 moles

The molar mass of the compounds is:

  • Al₂(SO₄)₃: 342 g/mole
  • KOH: 56.1 g/mole
  • Al(OH)₃: 78 g/mole
  • K₂SO₄: 174.2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al₂(SO₄)₃: 1 mole ×342 g/mole= 342 grams
  • KOH: 6 moles ×56.1 g/mole= 336.6 grams
  • Al(OH)₃: 2 moles ×78 g/mole= 156 grams
  • K₂SO₄: 3 moles ×174.2 g/mole= 522.6 grams

<h3>Definition of molarity</h3>

Molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume:

Molarity= number of moles÷ volume

<h3>Mass of Al(OH)₃ formed</h3>

In firts place, you know that 48.6 mL (0.0486 L) of 0.15 M KOH react with excess Al₂(SO₄)₃.

Replacing in the definition, you can calculate the amount of moles of KOH that react:

0.15 M= number of moles÷ 0.0486 L

Solving:

0.15 M× 0.0486 L= number of moles

<u><em>0.00729 moles= number of moles</em></u>

Then, 0.00729 moles of KOH react with excess Al₂(SO₄)₃. So, following rule of three can be applied: if by reaction stoichiometry 6 moles of KOH form 156 grams of Al(OH)₃, 0.00729 moles of KOH form how much mass of Na₂SO₄?

mass of Al(OH)_{3} =\frac{0.00729 moles of KOHx156 grams of Al(OH)_{3}}{6 moles of KOH}

<u><em>mass of Al(OH)₃= 0.18954 grams</em></u>

Then, 0.18954 grams of Al(OH)₃ are formed from the reaction of 48.6 mL (0.0486 L) of 0.15 M KOH with excess Al₂(SO₄)₃.

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