The answer is 79.9 g.
Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g
Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
Answer:
24.47 L
Explanation:
Using the general gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = 0.0821 Latm/molK
T = temperature (K)
According to the provided information in this question,
P = 1.0 atm
V = ?
n = 1 mol
T = 25°C = 25 + 273 = 298K
Using PV = nRT
V = nRT ÷ P
V = 1 × 0.0821 × 298 ÷ 1
V = 24.465 ÷ 1
V = 24.465
V = 24.47 L
Answer: Either give off or gain electrons to make a total of 8
Answer:
eye weakness is caused by deficiency of vitamin A
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